What are the solutions to the equation x^2+13x+6=0 ?

The solutions to the equation x^2+13x+6=0 are x=(-13+sqrt(145))/2 ,x=(-13-sqrt(145))/2

Find the zeros of x^2+13x+6=0

The zeros of x^2+13x+6=0 are x=(-13+sqrt(145))/2 ,x=(-13-sqrt(145))/2

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x^{2} + 13 x + 6 = 0

x = \frac{- 13 + 145}{2}, x = \frac{- 13 - 145}{2}

Decimal Notation

x = - 0.47920 \dots, x = - 12.52079 \dots

Solution steps

x^{2} + 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 6 = 145

x_{1, 2} = \frac{- 13 \pm 145}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 145}{2 \cdot 1}, x_{2} = \frac{- 13 - 145}{2 \cdot 1}

x = \frac{- 13 + 145}{2 \cdot 1} : \frac{- 13 + 145}{2}

x = \frac{- 13 - 145}{2 \cdot 1} : \frac{- 13 - 145}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 145}{2}, x = \frac{- 13 - 145}{2}

x + 2 + x = 22

\frac{1}{4 - 4 i}

\frac{1}{4} + 9

\frac{a - 4}{4 a - 8} + \frac{1}{2 a - 4}

x^{2} = 8 - x^{2}

What are the solutions to the equation x^2+13x+6=0 ?
The solutions to the equation x^2+13x+6=0 are x=(-13+sqrt(145))/2 ,x=(-13-sqrt(145))/2
Find the zeros of x^2+13x+6=0
The zeros of x^2+13x+6=0 are x=(-13+sqrt(145))/2 ,x=(-13-sqrt(145))/2