What are the solutions to the equation x^2+5x-9=0 ?

The solutions to the equation x^2+5x-9=0 are x=(-5+sqrt(61))/2 ,x=(-5-sqrt(61))/2

Find the zeros of x^2+5x-9=0

The zeros of x^2+5x-9=0 are x=(-5+sqrt(61))/2 ,x=(-5-sqrt(61))/2

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x^{2} + 5 x - 9 = 0

x = \frac{- 5 + 61}{2}, x = \frac{- 5 - 61}{2}

Decimal Notation

x = 1.40512 \dots, x = - 6.40512 \dots

Solution steps

x^{2} + 5 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 9) = 61

x_{1, 2} = \frac{- 5 \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 61}{2 \cdot 1}, x_{2} = \frac{- 5 - 61}{2 \cdot 1}

x = \frac{- 5 + 61}{2 \cdot 1} : \frac{- 5 + 61}{2}

x = \frac{- 5 - 61}{2 \cdot 1} : \frac{- 5 - 61}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 61}{2}, x = \frac{- 5 - 61}{2}

8 y^{2} - 30 y + 27 = 2

\frac{5}{15}

- 2 x - 3 \leq - 13

\frac{4}{5} \cdot 2

2 (x + 2) \geq 8 (3 - x)

What are the solutions to the equation x^2+5x-9=0 ?
The solutions to the equation x^2+5x-9=0 are x=(-5+sqrt(61))/2 ,x=(-5-sqrt(61))/2
Find the zeros of x^2+5x-9=0
The zeros of x^2+5x-9=0 are x=(-5+sqrt(61))/2 ,x=(-5-sqrt(61))/2