What are the solutions to the equation 8y^2-30y+27=2 ?

The solutions to the equation 8y^2-30y+27=2 are y= 5/2 ,y= 5/4

Find the zeros of 8y^2-30y+27=2

The zeros of 8y^2-30y+27=2 are y= 5/2 ,y= 5/4

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8 y^{2} - 30 y + 27 = 2

y = \frac{5}{2}, y = \frac{5}{4}

Decimal Notation

y = 2.5, y = 1.25

Solution steps

8 y^{2} - 30 y + 27 = 2

Move

2

to the left side

8 y^{2} - 30 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 8 \cdot 25}{2 \cdot 8}

(- 30)^{2} - 4 \cdot 8 \cdot 25 = 10

y_{1, 2} = \frac{- ( - 30 ) \pm 10}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- ( - 30 ) + 10}{2 \cdot 8}, y_{2} = \frac{- ( - 30 ) - 10}{2 \cdot 8}

y = \frac{- ( - 30 ) + 10}{2 \cdot 8} : \frac{5}{2}

y = \frac{- ( - 30 ) - 10}{2 \cdot 8} : \frac{5}{4}

The solutions to the quadratic equation are:

y = \frac{5}{2}, y = \frac{5}{4}

\frac{5}{15}

- 2 x - 3 \leq - 13

\frac{4}{5} \cdot 2

2 (x + 2) \geq 8 (3 - x)

(x - 2)^{2} - 6 (x - 2) + 5 = 0

What are the solutions to the equation 8y^2-30y+27=2 ?
The solutions to the equation 8y^2-30y+27=2 are y= 5/2 ,y= 5/4
Find the zeros of 8y^2-30y+27=2
The zeros of 8y^2-30y+27=2 are y= 5/2 ,y= 5/4