What is factor x^4+7x^3+12x^2-4x-16 ?

The solution to factor x^4+7x^3+12x^2-4x-16 is (x-1)(x+2)^2(x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^4+7x^3+12x^2-4x-16

factor

x^{4} + 7 x^{3} + 12 x^{2} - 4 x - 16

(x - 1) (x + 2)^{2} (x + 4)

Solution steps

x^{4} + 7 x^{3} + 12 x^{2} - 4 x - 16

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 7 x ^{3} + 12 x ^{2} - 4 x - 16}{x - 1}

\frac{x ^{4} + 7 x ^{3} + 12 x ^{2} - 4 x - 16}{x - 1} = x^{3} + 8 x^{2} + 20 x + 16

= (x - 1) (x^{3} + 8 x^{2} + 20 x + 16)

Factor

x^{3} + 8 x^{2} + 20 x + 16 : (x + 2) (x + 2) (x + 4)

= (x - 1) (x + 2) (x + 2) (x + 4)

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= (x - 1) (x + 2)^{2} (x + 4)

x^{3} + 9 x^{2} + 18 x

- \frac{1}{8} - \frac{1}{4}

\frac{146}{35} - \frac{64}{25}

5 \times 36

5 \times 21

What is factor x^4+7x^3+12x^2-4x-16 ?
The solution to factor x^4+7x^3+12x^2-4x-16 is (x-1)(x+2)^2(x+4)