What is 2/k-1/(k^2-1) ?

The solution to 2/k-1/(k^2-1) is (2k^2-2-k)/(k(k+1)(k-1))

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simplify 2/k-1/(k^2-1)

simplify

\frac{2}{k} - \frac{1}{k ^{2} - 1}

\frac{2 k ^{2} - 2 - k}{k ( k + 1 ) ( k - 1 )}

Solution steps

\frac{2}{k} - \frac{1}{k ^{2} - 1}

Least Common Multiplier of

k, k^{2} - 1 : k (k + 1) (k - 1)

Adjust Fractions based on the LCM

= \frac{2 ( k + 1 ) ( k - 1 )}{k ( k + 1 ) ( k - 1 )} - \frac{k}{k ( k + 1 ) ( k - 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{2 ( k + 1 ) ( k - 1 ) - k}{k ( k + 1 ) ( k - 1 )}

Simplify

2 (k + 1) (k - 1) - k : 2 k^{2} - 2 - k

= \frac{2 k ^{2} - 2 - k}{k ( k + 1 ) ( k - 1 )}

12 (5)

x (x - 3) (x - 4)

\frac{7}{8} \div \frac{3}{5}

- \frac{1}{3} \cdot (- 9)

(- 2 i) (2 i)

What is 2/k-1/(k^2-1) ?
The solution to 2/k-1/(k^2-1) is (2k^2-2-k)/(k(k+1)(k-1))