What is (49x^2-81)/(x^2-64)<= 0 ?

The solution to (49x^2-81)/(x^2-64)<= 0 is -8<x<=-9/7 \lor 9/7 <= x<8

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(49x^2-81)/(x^2-64)<= 0

\frac{49 x ^{2} - 81}{x ^{2} - 64} \leq 0

- 8 < x \leq - \frac{9}{7} or \frac{9}{7} \leq x < 8

Interval Notation

(- 8, - \frac{9}{7}] \cup [\frac{9}{7}, 8)

Decimal Notation

- 8 < x \leq - 1.28571 \dots or 1.28571 \dots \leq x < 8

Solution steps

\frac{49 x ^{2} - 81}{x ^{2} - 64} \leq 0

Factor

\frac{49 x ^{2} - 81}{x ^{2} - 64} : \frac{( 7 x + 9 ) ( 7 x - 9 )}{( x + 8 ) ( x - 8 )}

\frac{( 7 x + 9 ) ( 7 x - 9 )}{( x + 8 ) ( x - 8 )} \leq 0

Identify the intervals

- 8 < x \leq - \frac{9}{7} or \frac{9}{7} \leq x < 8

- 7 (m - 81) = - 91

- 1 < - (- 9 x - 1) - \frac{5}{2} x

6 a x - 15 x

\frac{2 y}{3} - \frac{3}{4} = \frac{1}{12}

y^{2} + 4 y - 21

What is (49x^2-81)/(x^2-64)<= 0 ?
The solution to (49x^2-81)/(x^2-64)<= 0 is -8<x<=-9/7 \lor 9/7 <= x<8