What is factor+x^3+6x^2+5x-12 ?

The solution to factor+x^3+6x^2+5x-12 is (x-1)(x+3)(x+4)

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factor+x^3+6x^2+5x-12

factor

+ x^{3} + 6 x^{2} + 5 x - 12

(x - 1) (x + 3) (x + 4)

Solution steps

x^{3} + 6 x^{2} + 5 x - 12

Use the rational root theorem

= (x - 1) \frac{x ^{3} + 6 x ^{2} + 5 x - 12}{x - 1}

\frac{x ^{3} + 6 x ^{2} + 5 x - 12}{x - 1} = x^{2} + 7 x + 12

= (x - 1) (x^{2} + 7 x + 12)

Factor

x^{2} + 7 x + 12 : (x + 3) (x + 4)

= (x - 1) (x + 3) (x + 4)

12 5^{- 2}

5 h^{5} \cdot (- 6 h^{2})

(5 x^{2} + 4)^{4}

y^{2} + 14 y + 24

4 r^{- 7} s^{- 1} \cdot 7 r^{- 2} s^{5} t^{0}

What is factor+x^3+6x^2+5x-12 ?
The solution to factor+x^3+6x^2+5x-12 is (x-1)(x+3)(x+4)