What are the solutions to the equation -2x^2+3x-6=0 ?

The solutions to the equation -2x^2+3x-6=0 are x= 3/4-i(sqrt(39))/4 ,x= 3/4+i(sqrt(39))/4

Find the zeros of -2x^2+3x-6=0

The zeros of -2x^2+3x-6=0 are x= 3/4-i(sqrt(39))/4 ,x= 3/4+i(sqrt(39))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 3 x - 6 = 0

x = \frac{3}{4} - i \frac{39}{4}, x = \frac{3}{4} + i \frac{39}{4}

Solution steps

- 2 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 6 )}{2 ( - 2 )}

Simplify

3^{2} - 4 (- 2) (- 6) : 39 i

x_{1, 2} = \frac{- 3 \pm 39 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 39 i}{2 ( - 2 )}, x_{2} = \frac{- 3 - 39 i}{2 ( - 2 )}

x = \frac{- 3 + 39 i}{2 ( - 2 )} : \frac{3}{4} - i \frac{39}{4}

x = \frac{- 3 - 39 i}{2 ( - 2 )} : \frac{3}{4} + i \frac{39}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{39}{4}, x = \frac{3}{4} + i \frac{39}{4}

\frac{x}{3} \leq 3

x^{2} + 6 x - 24 = 0

64 x^{3} - 1

x^{3} - 2 x^{2} + x \geq 0

What are the solutions to the equation -2x^2+3x-6=0 ?
The solutions to the equation -2x^2+3x-6=0 are x= 3/4-i(sqrt(39))/4 ,x= 3/4+i(sqrt(39))/4
Find the zeros of -2x^2+3x-6=0
The zeros of -2x^2+3x-6=0 are x= 3/4-i(sqrt(39))/4 ,x= 3/4+i(sqrt(39))/4