What is 4/(x^2-3x+2)+7/(x^2-1) ?

The solution to 4/(x^2-3x+2)+7/(x^2-1) is (11x-10)/((x-1)(x-2)(x+1))

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simplify 4/(x^2-3x+2)+7/(x^2-1)

simplify

\frac{4}{x ^{2} - 3 x + 2} + \frac{7}{x ^{2} - 1}

\frac{11 x - 10}{( x - 1 ) ( x - 2 ) ( x + 1 )}

Solution steps

\frac{4}{x ^{2} - 3 x + 2} + \frac{7}{x ^{2} - 1}

Least Common Multiplier of

x^{2} - 3 x + 2, x^{2} - 1 : (x - 1) (x - 2) (x + 1)

Adjust Fractions based on the LCM

= \frac{4 ( x + 1 )}{( x - 1 ) ( x - 2 ) ( x + 1 )} + \frac{7 ( x - 2 )}{( x - 1 ) ( x - 2 ) ( x + 1 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{4 ( x + 1 ) + 7 ( x - 2 )}{( x - 1 ) ( x - 2 ) ( x + 1 )}

Simplify

4 (x + 1) + 7 (x - 2) : 11 x - 10

= \frac{11 x - 10}{( x - 1 ) ( x - 2 ) ( x + 1 )}

- 4 + - 25 - 4 + - 16

\frac{4 x ^{3}}{x ^{2} + 3 x}

(9 x - 5 y) + (3 x + 2 y - 7)

7. 4^{2}

\frac{2}{3} \times \frac{4}{7}

What is 4/(x^2-3x+2)+7/(x^2-1) ?
The solution to 4/(x^2-3x+2)+7/(x^2-1) is (11x-10)/((x-1)(x-2)(x+1))