What is (4x^3+16x^2-29x+10)/(2x-1) ?

The solution to (4x^3+16x^2-29x+10)/(2x-1) is 2x^2+9x-10

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simplify (4x^3+16x^2-29x+10)/(2x-1)

simplify

\frac{4 x ^{3} + 16 x ^{2} - 29 x + 10}{2 x - 1}

2 x^{2} + 9 x - 10

Solution steps

\frac{4 x ^{3} + 16 x ^{2} - 29 x + 10}{2 x - 1}

Factor

4 x^{3} + 16 x^{2} - 29 x + 10 : (2 x - 1) (2 x^{2} + 9 x - 10)

= \frac{( 2 x - 1 ) ( 2 x ^{2} + 9 x - 10 )}{2 x - 1}

Cancel the common factor:

2 x - 1

= 2 x^{2} + 9 x - 10

+ 4 c^{2} - 1

- \frac{1}{4} + \frac{3}{5}

32.7 + (- 51.82)

(x^{2} + 1)^{5}

34 \times 5

What is (4x^3+16x^2-29x+10)/(2x-1) ?
The solution to (4x^3+16x^2-29x+10)/(2x-1) is 2x^2+9x-10