What is (x+y^2}{x^2}+\frac{x-1)/x-1 ?

The solution to (x+y^2}{x^2}+\frac{x-1)/x-1 is (y^2)/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x+y^2}{x^2}+\frac{x-1)/x-1

simplify

\frac{x + y ^{2}}{x ^{2}} + \frac{x - 1}{x} - 1

\frac{y ^{2}}{x ^{2}}

Solution steps

\frac{x + y ^{2}}{x ^{2}} + \frac{x - 1}{x} - 1

Join

\frac{x + y ^{2}}{x ^{2}} + \frac{x - 1}{x} : \frac{x + y ^{2} + ( x - 1 ) x}{x ^{2}}

= \frac{x + y ^{2} + ( x - 1 ) x}{x ^{2}} - 1

Apply the fraction rule:

a + \frac{b}{c} = \frac{a c + b}{c}

= \frac{- 1 \cdot x ^{2} + x + y ^{2} + ( x - 1 ) x}{x ^{2}}

Apply rule:

1 \cdot a = a

- 1 \cdot x^{2} = - x^{2}

= \frac{- x ^{2} + x + y ^{2} + ( x - 1 ) x}{x ^{2}}

Simplify

- x^{2} + x + y^{2} + (x - 1) x : y^{2}

= \frac{y ^{2}}{x ^{2}}

x^{2} - 15 x + 14

\frac{1}{5} \div \frac{4}{5}

- 7 \times 1

5 x^{3} - 7 x^{2} - 45 x + 63

9^{2 l o g_{3} (5)}

What is (x+y^2}{x^2}+\frac{x-1)/x-1 ?
The solution to (x+y^2}{x^2}+\frac{x-1)/x-1 is (y^2)/(x^2)