What is (x^7y^{14}s^{-21})^{-1/3} ?

The solution to (x^7y^{14}s^{-21})^{-1/3} is (s^7)/(x^{7/3)y^{14/3}}

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simplify (x^7y^{14}s^{-21})^{-1/3}

simplify

(x^{7} y^{14} s^{- 21})^{- \frac{1}{3}}

\frac{s ^{7}}{x ^{\frac{7}{3}} y ^{\frac{14}{3}}}

Solution steps

(x^{7} y^{14} s^{- 21})^{- \frac{1}{3}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(x^{7} y^{14} s^{- 21})^{- \frac{1}{3}} = \frac{1}{( x ^{7} y ^{14} s ^{- 21} ) ^{\frac{1}{3}}}

= \frac{1}{( x ^{7} y ^{14} s ^{- 21} ) ^{\frac{1}{3}}}

Simplify

(x^{7} y^{14} s^{- 21})^{\frac{1}{3}} : \frac{x ^{\frac{7}{3}} y ^{\frac{14}{3}}}{s ^{7}}

= \frac{1}{\frac{x ^{\frac{7}{3}} y ^{\frac{14}{3}}}{s ^{7}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{s ^{7}}{x ^{\frac{7}{3}} y ^{\frac{14}{3}}}

3 \frac{3}{4} \div 2 \frac{1}{2}

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\frac{46}{17} - 3

- 6 - 3

2 \times 4

What is (x^7y^{14}s^{-21})^{-1/3} ?
The solution to (x^7y^{14}s^{-21})^{-1/3} is (s^7)/(x^{7/3)y^{14/3}}