What are the solutions to the equation X^2+4X+2=0 ?

The solutions to the equation X^2+4X+2=0 are X=-2+sqrt(2),X=-2-sqrt(2)

Find the zeros of X^2+4X+2=0

The zeros of X^2+4X+2=0 are X=-2+sqrt(2),X=-2-sqrt(2)

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X^{2} + 4 X + 2 = 0

X = - 2 + 2, X = - 2 - 2

Solution steps

X^{2} + 4 X + 2 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

X_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, X_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

X = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

X = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

X = - 2 + 2, X = - 2 - 2

2 n^{2} + 6 n - 108

8 w^{3} - 125

(8^{\frac{3}{4}} + 2^{3})^{\frac{1}{2}}

3 x^{2} - 5 x - 2 \leq 0

u^{4} - u^{2} v^{2} - 20 v^{4}

What are the solutions to the equation X^2+4X+2=0 ?
The solutions to the equation X^2+4X+2=0 are X=-2+sqrt(2),X=-2-sqrt(2)
Find the zeros of X^2+4X+2=0
The zeros of X^2+4X+2=0 are X=-2+sqrt(2),X=-2-sqrt(2)