What are the solutions to the equation (x-4)(x+2)=16 ?

The solutions to the equation (x-4)(x+2)=16 are x=6,x=-4

Find the zeros of (x-4)(x+2)=16

The zeros of (x-4)(x+2)=16 are x=6,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 4) (x + 2) = 16

x = 6, x = - 4

Solution steps

(x - 4) (x + 2) = 16

Expand

(x - 4) (x + 2) : x^{2} - 2 x - 8

x^{2} - 2 x - 8 = 16

Move

16

to the left side

x^{2} - 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

x = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

(x + 1)^{2} (x - 3) (x - 8) < 0

9 x^{2} - 7 = 0

36 x^{2} - 49 y^{2}

1 (\frac{3}{7})^{2}

49 - 16 x^{2} y^{2}

What are the solutions to the equation (x-4)(x+2)=16 ?
The solutions to the equation (x-4)(x+2)=16 are x=6,x=-4
Find the zeros of (x-4)(x+2)=16
The zeros of (x-4)(x+2)=16 are x=6,x=-4