What is factor 2x^3+5x^2-28x-15 ?

The solution to factor 2x^3+5x^2-28x-15 is (2x+1)(x-3)(x+5)

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factor 2x^3+5x^2-28x-15

factor

2 x^{3} + 5 x^{2} - 28 x - 15

(2 x + 1) (x - 3) (x + 5)

Solution steps

2 x^{3} + 5 x^{2} - 28 x - 15

Use the rational root theorem

= (2 x + 1) \frac{2 x ^{3} + 5 x ^{2} - 28 x - 15}{2 x + 1}

\frac{2 x ^{3} + 5 x ^{2} - 28 x - 15}{2 x + 1} = x^{2} + 2 x - 15

= (2 x + 1) (x^{2} + 2 x - 15)

Factor

x^{2} + 2 x - 15 : (x - 3) (x + 5)

= (2 x + 1) (x - 3) (x + 5)

(13 x - 11) (13 x - 15)

f (x) = \frac{2 x ^{2} - 18}{x ^{2} - 6 x + 9}

\frac{\frac{x}{x - 2}}{\frac{3 x}{x + 4}}

8 - 5 (4 p + 3)

What is factor 2x^3+5x^2-28x-15 ?
The solution to factor 2x^3+5x^2-28x-15 is (2x+1)(x-3)(x+5)