What are the solutions to the equation x^2+33=14x ?

The solutions to the equation x^2+33=14x are x=11,x=3

Find the zeros of x^2+33=14x

The zeros of x^2+33=14x are x=11,x=3

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x^{2} + 33 = 14 x

x = 11, x = 3

Solution steps

x^{2} + 33 = 14 x

Move

14 x

to the left side

x^{2} + 33 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 14 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 33 = 8

x_{1, 2} = \frac{- ( - 14 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8}{2 \cdot 1} : 11

x = \frac{- ( - 14 ) - 8}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 11, x = 3

∣ x - 2 ∣ \leq 7

2^{x} \cdot 3^{x}

225 x^{2} - 36

\frac{( x + 8 )}{x - 5} \leq 0

125 x^{3} - 216

What are the solutions to the equation x^2+33=14x ?
The solutions to the equation x^2+33=14x are x=11,x=3
Find the zeros of x^2+33=14x
The zeros of x^2+33=14x are x=11,x=3