What is (12x^3y^4z^5)/(32xy^2z) ?

The solution to (12x^3y^4z^5)/(32xy^2z) is (3x^2y^2z^4)/8

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simplify (12x^3y^4z^5)/(32xy^2z)

simplify

\frac{12 x ^{3} y ^{4} z ^{5}}{32 x y ^{2} z}

\frac{3 x ^{2} y ^{2} z ^{4}}{8}

Solution steps

\frac{12 x ^{3} y ^{4} z ^{5}}{32 x y ^{2} z}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 3 x ^{3} y ^{4} z ^{5}}{32 x y ^{2} z}

Factor the number:

32 = 4 \cdot 8

= \frac{4 \cdot 3 x ^{3} y ^{4} z ^{5}}{4 \cdot 8 x y ^{2} z}

Cancel the common factor:

4

= \frac{3 x ^{3} y ^{4} z ^{5}}{8 x y ^{2} z}

Simplify

\frac{x ^{3}}{x} : x^{2}

= \frac{3 x ^{2} y ^{4} z ^{5}}{8 y ^{2} z}

Simplify

\frac{y ^{4}}{y ^{2}} : y^{2}

= \frac{3 x ^{2} y ^{2} z ^{5}}{8 z}

Simplify

\frac{z ^{5}}{z} : z^{4}

= \frac{3 x ^{2} y ^{2} z ^{4}}{8}

(q + 7) (q - 2)

ln (0.00000001)

\frac{93}{4}

\frac{93}{2}

\frac{400}{2}

What is (12x^3y^4z^5)/(32xy^2z) ?
The solution to (12x^3y^4z^5)/(32xy^2z) is (3x^2y^2z^4)/8