What is e^{(i2pi)/3} ?

The solution to e^{(i2pi)/3} is -1/2+i(sqrt(3))/2

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simplify e^{(i2pi)/3}

simplify

e^{\frac{i 2 π}{3}}

- \frac{1}{2} + i \frac{3}{2}

Solution steps

e^{\frac{i 2 π}{3}}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= cos (\frac{2 π}{3}) + i sin (\frac{2 π}{3})

Use the following trivial identity:

cos (\frac{2 π}{3}) = - \frac{1}{2}

Use the following trivial identity:

sin (\frac{2 π}{3}) = \frac{3}{2}

= - \frac{1}{2} + \frac{3}{2} i

(3 x + 4) (x + 2)

125 - 64 r^{3}

(x + x)^{2}

5 \frac{1}{8} - 1 \frac{1}{2}

2 + \frac{1}{x + 1}