What are the solutions to the equation m^2+4m=0 ?

The solutions to the equation m^2+4m=0 are m=0,m=-4

Find the zeros of m^2+4m=0

The zeros of m^2+4m=0 are m=0,m=-4

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m^{2} + 4 m = 0

m = 0, m = - 4

Solution steps

m^{2} + 4 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

m_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 4}{2 \cdot 1}, m_{2} = \frac{- 4 - 4}{2 \cdot 1}

m = \frac{- 4 + 4}{2 \cdot 1} : 0

m = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = 0, m = - 4

7 \cdot 4 = 1 + k \cdot 160

x^{3} + 2 x^{2} + 4 x + 8

\frac{6}{x - 5} \leq \frac{5}{x - 4}

x^{- \frac{3}{2}} + 2 x^{- \frac{1}{2}} + x^{\frac{1}{2}}

(62 + 2 X) (54 + 2 X)

What are the solutions to the equation m^2+4m=0 ?
The solutions to the equation m^2+4m=0 are m=0,m=-4
Find the zeros of m^2+4m=0
The zeros of m^2+4m=0 are m=0,m=-4