What is expand (x+1)(x-2)(x+4)(3x+7) ?

The solution to expand (x+1)(x-2)(x+4)(3x+7) is 3x^4+16x^3+3x^2-66x-56

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expand (x+1)(x-2)(x+4)(3x+7)

expand

(x + 1) (x - 2) (x + 4) (3 x + 7)

3 x^{4} + 16 x^{3} + 3 x^{2} - 66 x - 56

Solution steps

(x + 1) (x - 2) (x + 4) (3 x + 7)

Expand

(x + 1) (x - 2) (x + 4) (3 x + 7) : (x^{2} - x - 2) (x + 4) (3 x + 7)

= (x^{2} - x - 2) (x + 4) (3 x + 7)

Apply FOIL method

(x + 4) (3 x + 7) : 3 x^{2} + 19 x + 28

= (x^{2} - x - 2) (3 x^{2} + 19 x + 28)

Distribute parentheses

= x^{2} \cdot 3 x^{2} + x^{2} \cdot 19 x + x^{2} \cdot 28 - x \cdot 3 x^{2} - x \cdot 19 x - x \cdot 28 - 2 \cdot 3 x^{2} - 2 \cdot 19 x - 2 \cdot 28

Simplify

x^{2} \cdot 3 x^{2} + x^{2} \cdot 19 x + x^{2} \cdot 28 - x \cdot 3 x^{2} - x \cdot 19 x - x \cdot 28 - 2 \cdot 3 x^{2} - 2 \cdot 19 x - 2 \cdot 28 : 3 x^{4} + 16 x^{3} + 3 x^{2} - 66 x - 56

= 3 x^{4} + 16 x^{3} + 3 x^{2} - 66 x - 56

\frac{7}{5 x - 2 a}

\frac{12 3 ^{2}}{12 3 ^{3}}

+ \frac{4}{3} π (8)^{3}

\frac{i}{( 4 - 5 i ) ^{2}}

\frac{i + 2}{i - 1}

What is expand (x+1)(x-2)(x+4)(3x+7) ?
The solution to expand (x+1)(x-2)(x+4)(3x+7) is 3x^4+16x^3+3x^2-66x-56