What is (-16x^2y^7)/(12x^5y^3z^4) ?

The solution to (-16x^2y^7)/(12x^5y^3z^4) is -(4y^4)/(3x^3z^4)

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simplify (-16x^2y^7)/(12x^5y^3z^4)

simplify

\frac{- 16 x ^{2} y ^{7}}{12 x ^{5} y ^{3} z ^{4}}

- \frac{4 y ^{4}}{3 x ^{3} z ^{4}}

Solution steps

\frac{- 16 x ^{2} y ^{7}}{12 x ^{5} y ^{3} z ^{4}}

Factor the number:

16 = 4 \cdot 4

= \frac{- 4 \cdot 4 x ^{2} y ^{7}}{12 x ^{5} y ^{3} z ^{4}}

Factor the number:

12 = 4 \cdot 3

= \frac{- 4 \cdot 4 x ^{2} y ^{7}}{4 \cdot 3 x ^{5} y ^{3} z ^{4}}

Cancel the common factor:

4

= \frac{- 4 x ^{2} y ^{7}}{3 x ^{5} y ^{3} z ^{4}}

Simplify

\frac{y ^{7}}{y ^{3}} : y^{4}

= \frac{- 4 x ^{2} y ^{4}}{3 x ^{5} z ^{4}}

Simplify

\frac{x ^{2}}{x ^{5}} : \frac{1}{x ^{3}}

= \frac{- 4 y ^{4}}{3 x ^{3} z ^{4}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4 y ^{4}}{3 x ^{3} z ^{4}}

7 \cdot 32

7 \cdot 19

7 \cdot (- 6)

\frac{2 5}{10}

3 x^{4} + 6 x^{3} + 27 x^{2}

What is (-16x^2y^7)/(12x^5y^3z^4) ?
The solution to (-16x^2y^7)/(12x^5y^3z^4) is -(4y^4)/(3x^3z^4)