What is log_{7}(9)+log_{7}(4) ?

The solution to log_{7}(9)+log_{7}(4) is 2log_{7}(6)

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simplify log_{7}(9)+log_{7}(4)

simplify

lo g_{7} (9) + lo g_{7} (4)

2 lo g_{7} (6)

Decimal Notation

1.84156 \dots

Solution steps

lo g_{7} (9) + lo g_{7} (4)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{7} (9) + lo g_{7} (4) = lo g_{7} (9 \cdot 4)

= lo g_{7} (9 \cdot 4)

Multiply the numbers:

9 \cdot 4 = 36

= lo g_{7} (36)

Factor the number:

36 = 6^{2}

= lo g_{7} (6^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x), x > 0

lo g_{7} (6^{2}) = 2 lo g_{7} (6)

= 2 lo g_{7} (6)

3 x - 2 = 2 x - 4

(\frac{π}{4})^{2}

\frac{1}{4} (b - 7) = 8

3 d + d - 7 = \frac{25}{4}

25 x^{2} + 1 = 10

What is log_{7}(9)+log_{7}(4) ?
The solution to log_{7}(9)+log_{7}(4) is 2log_{7}(6)