What is (e^{-2}(2)^2)/(2!) ?

The solution to (e^{-2}(2)^2)/(2!) is 2/(e^2)

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simplify (e^{-2}(2)^2)/(2!)

simplify

\frac{e ^{- 2} ( 2 ) ^{2}}{2 !}

\frac{2}{e ^{2}}

Decimal Notation

0.27067 \dots

Solution steps

\frac{e ^{- 2} \cdot 2 ^{2}}{2 !}

Multiply

e^{- 2} \cdot 2^{2} : \frac{4}{e ^{2}}

= \frac{\frac{4}{e ^{2}}}{2 !}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4}{e ^{2} \cdot 2 !}

e^{2} \cdot 2! = 2 e^{2}

= \frac{4}{2 e ^{2}}

Divide the numbers:

\frac{4}{2} = 2

= \frac{2}{e ^{2}}

- \frac{6}{3}

\frac{1}{4} + \frac{4}{7}

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