What are the solutions to the equation x^2+2x+37=0 ?

The solutions to the equation x^2+2x+37=0 are x=-1+6i,x=-1-6i

Find the zeros of x^2+2x+37=0

The zeros of x^2+2x+37=0 are x=-1+6i,x=-1-6i

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x^{2} + 2 x + 37 = 0

x = - 1 + 6 i, x = - 1 - 6 i

Solution steps

x^{2} + 2 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 37 : 12 i

x_{1, 2} = \frac{- 2 \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 12 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 12 i}{2 \cdot 1}

x = \frac{- 2 + 12 i}{2 \cdot 1} : - 1 + 6 i

x = \frac{- 2 - 12 i}{2 \cdot 1} : - 1 - 6 i

The solutions to the quadratic equation are:

x = - 1 + 6 i, x = - 1 - 6 i

5 x + 2 x = 21

\frac{8}{3} + (- \frac{9}{4})

\frac{x}{- 4} = 8

e^{2 x} \cdot e^{2 x}

(6)^{3}

What are the solutions to the equation x^2+2x+37=0 ?
The solutions to the equation x^2+2x+37=0 are x=-1+6i,x=-1-6i
Find the zeros of x^2+2x+37=0
The zeros of x^2+2x+37=0 are x=-1+6i,x=-1-6i