What is (2i^2)(-3i^2) ?

The solution to (2i^2)(-3i^2) is -6

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simplify (2i^2)(-3i^2)

simplify

(2 i^{2}) (- 3 i^{2})

- 6

Solution steps

(2 i^{2}) (- 3 i^{2})

Apply rule:

a (- b) = - ab

(2 i^{2}) (- 3 i^{2}) = - 2 i^{2} \cdot 3 i^{2}

= - 2 i^{2} \cdot 3 i^{2}

Multiply the numbers:

- 2 \cdot 3 = - 6

= - 6 i^{2} i^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

i^{2} i^{2} = i^{2 + 2}

= - 6 i^{2 + 2}

Add the numbers:

2 + 2 = 4

= - 6 i^{4}

Apply exponent rule:

a^{b c} = (a^{b})^{c}

i^{4} = (i^{2})^{2}

= - 6 (i^{2})^{2}

Apply imaginary number rule:

i^{2} = - 1

= - 6 (- 1)^{2}

(- 1)^{2} = 1

= - 6 \cdot 1

Multiply the numbers:

- 6 \cdot 1 = - 6

= - 6

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