What is (12x^3+12x^2)/(x^4-x^2) ?

The solution to (12x^3+12x^2)/(x^4-x^2) is (12)/(x-1)

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simplify (12x^3+12x^2)/(x^4-x^2)

simplify

\frac{12 x ^{3} + 12 x ^{2}}{x ^{4} - x ^{2}}

\frac{12}{x - 1}

Solution steps

\frac{12 x ^{3} + 12 x ^{2}}{x ^{4} - x ^{2}}

Factor

12 x^{3} + 12 x^{2} : 12 x^{2} (x + 1)

= \frac{12 x ^{2} ( x + 1 )}{x ^{4} - x ^{2}}

Factor

x^{4} - x^{2} : x^{2} (x + 1) (x - 1)

= \frac{12 x ^{2} ( x + 1 )}{x ^{2} ( x + 1 ) ( x - 1 )}

Cancel the common factor:

x^{2}

= \frac{12 ( x + 1 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x + 1

= \frac{12}{x - 1}

175 \div 25

(5 x + 1)^{2}

\frac{7}{5} + 1

\frac{7}{35}

What is (12x^3+12x^2)/(x^4-x^2) ?
The solution to (12x^3+12x^2)/(x^4-x^2) is (12)/(x-1)