What is factor 64+27y^3 ?

The solution to factor 64+27y^3 is (3y+4)(9y^2-12y+16)

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factor 64+27y^3

factor

64 + 27 y^{3}

(3 y + 4) (9 y^{2} - 12 y + 16)

Solution steps

64 + 27 y^{3}

Write in the standard form

= 27 y^{3} + 64

Apply exponent rules

= (3 y)^{3} + 4^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 y)^{3} + 4^{3} = (3 y + 4) (3^{2} y^{2} - 4 \cdot 3 y + 4^{2})

= (3 y + 4) (3^{2} y^{2} - 4 \cdot 3 y + 4^{2})

Simplify

(3 y + 4) (3^{2} y^{2} - 4 \cdot 3 y + 4^{2}) : (3 y + 4) (9 y^{2} - 12 y + 16)

= (3 y + 4) (9 y^{2} - 12 y + 16)

\frac{50}{55}

\frac{π}{4} \times \frac{180}{π}

3 w - 4 (- 6 z + 4 w) + 7 z

\frac{3}{6} + \frac{4}{5}

What is factor 64+27y^3 ?
The solution to factor 64+27y^3 is (3y+4)(9y^2-12y+16)