What are the solutions to the equation w^2-10w+24=0 ?

The solutions to the equation w^2-10w+24=0 are w=6,w=4

Find the zeros of w^2-10w+24=0

The zeros of w^2-10w+24=0 are w=6,w=4

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w^{2} - 10 w + 24 = 0

w = 6, w = 4

Solution steps

w^{2} - 10 w + 24 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

w_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, w_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

w = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

w = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

w = 6, w = 4

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What are the solutions to the equation w^2-10w+24=0 ?
The solutions to the equation w^2-10w+24=0 are w=6,w=4
Find the zeros of w^2-10w+24=0
The zeros of w^2-10w+24=0 are w=6,w=4