What is (e^{2t}-e^{-2t})/(e^{2t)+e^{-2t}} ?

The solution to (e^{2t}-e^{-2t})/(e^{2t)+e^{-2t}} is (e^{4t}-1)/(e^{4t)+1}

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simplify (e^{2t}-e^{-2t})/(e^{2t)+e^{-2t}}

simplify

\frac{e ^{2 t} - e ^{- 2 t}}{e ^{2 t} + e ^{- 2 t}}

\frac{e ^{4 t} - 1}{e ^{4 t} + 1}

Solution steps

\frac{e ^{2 t} - e ^{- 2 t}}{e ^{2 t} + e ^{- 2 t}}

Factor

e^{2 t} - e^{- 2 t} : e^{- 2 t} (e^{4 t} - 1)

= \frac{e ^{- 2 t} ( e ^{4 t} - 1 )}{e ^{2 t} + e ^{- 2 t}}

Factor

e^{2 t} + e^{- 2 t} : e^{- 2 t} (e^{4 t} + 1)

= \frac{e ^{- 2 t} ( e ^{4 t} - 1 )}{e ^{- 2 t} ( e ^{4 t} + 1 )}

Cancel the common factor:

e^{- 2 t}

= \frac{e ^{4 t} - 1}{e ^{4 t} + 1}

3 + 27 + 12

7 + - 9

\frac{d ^{2}}{d ^{2} x} (x^{2})

a^{3} + b^{3}

\frac{7 i}{- 4 + 8 i}

What is (e^{2t}-e^{-2t})/(e^{2t)+e^{-2t}} ?
The solution to (e^{2t}-e^{-2t})/(e^{2t)+e^{-2t}} is (e^{4t}-1)/(e^{4t)+1}