What is 1/(sqrt(16-x^2)) ?

The solution to 1/(sqrt(16-x^2)) is (sqrt(16-x^2))/(16-x^2)

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simplify 1/(sqrt(16-x^2))

simplify

\frac{1}{16 - x ^{2}}

\frac{16 - x ^{2}}{16 - x ^{2}}

Solution steps

\frac{1}{16 - x ^{2}}

Multiply by the conjugate

\frac{16 - x ^{2}}{16 - x ^{2}}

= \frac{1 \cdot 16 - x ^{2}}{16 - x ^{2} 16 - x ^{2}}

1 \cdot 16 - x^{2} = 16 - x^{2}

16 - x^{2} 16 - x^{2} = 16 - x^{2}

= \frac{16 - x ^{2}}{16 - x ^{2}}

\frac{x ^{2} - 9}{3 + x}

\frac{3}{8} \div 6

m^{4} + 2 m^{2} + 1

x^{2} + 6 \times + 9

What is 1/(sqrt(16-x^2)) ?
The solution to 1/(sqrt(16-x^2)) is (sqrt(16-x^2))/(16-x^2)