What are the solutions to the equation x^2+4x=77 ?

The solutions to the equation x^2+4x=77 are x=7,x=-11

Find the zeros of x^2+4x=77

The zeros of x^2+4x=77 are x=7,x=-11

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x^{2} + 4 x = 77

x = 7, x = - 11

Solution steps

x^{2} + 4 x = 77

Move

77

to the left side

x^{2} + 4 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 77 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 77) = 18

x_{1, 2} = \frac{- 4 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 18}{2 \cdot 1}, x_{2} = \frac{- 4 - 18}{2 \cdot 1}

x = \frac{- 4 + 18}{2 \cdot 1} : 7

x = \frac{- 4 - 18}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 7, x = - 11

\frac{x - y}{y ^{2} + x y - 2 x ^{2}}

x^{2} - 5 x - 14 < 0

1 - x - x^{2} + x^{3}

(- 8) (- 8)

- 4 x + 2 (\frac{22}{10}) = 6

What are the solutions to the equation x^2+4x=77 ?
The solutions to the equation x^2+4x=77 are x=7,x=-11
Find the zeros of x^2+4x=77
The zeros of x^2+4x=77 are x=7,x=-11