What is factor 16x^2-8xy+y^2 ?

The solution to factor 16x^2-8xy+y^2 is (4x-y)^2

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factor 16x^2-8xy+y^2

factor

16 x^{2} - 8 x y + y^{2}

(4 x - y)^{2}

Solution steps

16 x^{2} - 8 x y + y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 x^{2} = (4 x)^{2}

- 8 x y = - 2 \cdot 4 x y

= (4 x)^{2} - 2 \cdot 4 x y + y^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(4 x)^{2} - 2 \cdot 4 x y + y^{2} = (4 x - y)^{2}

= (4 x - y)^{2}

- 7 \times 9

1 + \frac{2}{9}

4 u - 6 u

2 x^{2} (x^{2})

\frac{\frac{8}{5}}{2}