What is (12+x^4+2x^3-8x-7x^2)/(x-1) ?

The solution to (12+x^4+2x^3-8x-7x^2)/(x-1) is (x+3)(x+2)(x-2)

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simplify (12+x^4+2x^3-8x-7x^2)/(x-1)

simplify

\frac{12 + x ^{4} + 2 x ^{3} - 8 x - 7 x ^{2}}{x - 1}

(x + 3) (x + 2) (x - 2)

Solution steps

\frac{12 + x ^{4} + 2 x ^{3} - 8 x - 7 x ^{2}}{x - 1}

Factor

12 + x^{4} + 2 x^{3} - 8 x - 7 x^{2} : (x - 1) (x + 3) (x + 2) (x - 2)

= \frac{( x - 1 ) ( x + 3 ) ( x + 2 ) ( x - 2 )}{x - 1}

Cancel the common factor:

x - 1

= (x + 3) (x + 2) (x - 2)

x^{2} (1)

\frac{x ^{- 6} y}{x ^{8} y ^{6}}

\frac{1 + \frac{5}{c - 5}}{1 - \frac{5}{c - 5}}

196 x^{2} - 144

(2 b - 3) (- 9)

What is (12+x^4+2x^3-8x-7x^2)/(x-1) ?
The solution to (12+x^4+2x^3-8x-7x^2)/(x-1) is (x+3)(x+2)(x-2)