What is (3x^2-7x-20)/(2x^2-5x-12) ?

The solution to (3x^2-7x-20)/(2x^2-5x-12) is (3x+5)/(2x+3)

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simplify (3x^2-7x-20)/(2x^2-5x-12)

simplify

\frac{3 x ^{2} - 7 x - 20}{2 x ^{2} - 5 x - 12}

\frac{3 x + 5}{2 x + 3}

Solution steps

\frac{3 x ^{2} - 7 x - 20}{2 x ^{2} - 5 x - 12}

Factor

3 x^{2} - 7 x - 20 : (3 x + 5) (x - 4)

= \frac{( 3 x + 5 ) ( x - 4 )}{2 x ^{2} - 5 x - 12}

Factor

2 x^{2} - 5 x - 12 : (2 x + 3) (x - 4)

= \frac{( 3 x + 5 ) ( x - 4 )}{( 2 x + 3 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{3 x + 5}{2 x + 3}

(2 x^{3} - 1)^{3}

0 - 16

0 - 30

3 + 312

2 - - 9

What is (3x^2-7x-20)/(2x^2-5x-12) ?
The solution to (3x^2-7x-20)/(2x^2-5x-12) is (3x+5)/(2x+3)