What are the solutions to the equation x^2-x-182=0 ?

The solutions to the equation x^2-x-182=0 are x=14,x=-13

Find the zeros of x^2-x-182=0

The zeros of x^2-x-182=0 are x=14,x=-13

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x^{2} - x - 182 = 0

x = 14, x = - 13

Solution steps

x^{2} - x - 182 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 182 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 182) = 27

x_{1, 2} = \frac{- ( - 1 ) \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 27}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 27}{2 \cdot 1}

x = \frac{- ( - 1 ) + 27}{2 \cdot 1} : 14

x = \frac{- ( - 1 ) - 27}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 14, x = - 13

t^{2} - 15 t + 50

(3 q + 2)^{2} = 0

7 x^{2} + 42 = 0

(6 x - 15 y - 36) \cdot \frac{1}{3}

- x + 2 = 5

What are the solutions to the equation x^2-x-182=0 ?
The solutions to the equation x^2-x-182=0 are x=14,x=-13
Find the zeros of x^2-x-182=0
The zeros of x^2-x-182=0 are x=14,x=-13