What are the solutions to the equation x^2+6x+9=1 ?

The solutions to the equation x^2+6x+9=1 are x=-2,x=-4

Find the zeros of x^2+6x+9=1

The zeros of x^2+6x+9=1 are x=-2,x=-4

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x^{2} + 6 x + 9 = 1

x = - 2, x = - 4

Solution steps

x^{2} + 6 x + 9 = 1

Move

1

to the left side

x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2}{2 \cdot 1}

x = \frac{- 6 + 2}{2 \cdot 1} : - 2

x = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

10 (x + 12) + 8 = 258

\frac{2 !}{1 ! ( 2 - 1 ) !}

\frac{- 2 - 3 i}{6 i}

\frac{9 !}{( 9 - 8 ) ! 8 !}

10 - v > 0

What are the solutions to the equation x^2+6x+9=1 ?
The solutions to the equation x^2+6x+9=1 are x=-2,x=-4
Find the zeros of x^2+6x+9=1
The zeros of x^2+6x+9=1 are x=-2,x=-4