What is (1/(k^{1-a)})/(k^{1-a)} ?

The solution to (1/(k^{1-a)})/(k^{1-a)} is 1/(k^{2(1-a))}

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simplify (1/(k^{1-a)})/(k^{1-a)}

simplify

\frac{\frac{1}{k ^{1 - a}}}{k ^{1 - a}}

\frac{1}{k ^{2 (1 - a)}}

Solution steps

\frac{\frac{1}{k ^{1 - a}}}{k ^{1 - a}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{k ^{1 - a} k ^{1 - a}}

Simplify

k^{1 - a} k^{1 - a} : k^{2 (1 - a)}

= \frac{1}{k ^{2 (1 - a)}}

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What is (1/(k^{1-a)})/(k^{1-a)} ?
The solution to (1/(k^{1-a)})/(k^{1-a)} is 1/(k^{2(1-a))}