What are the solutions to the equation 6x^2+5x+1=0 ?

The solutions to the equation 6x^2+5x+1=0 are x=-1/3 ,x=-1/2

Find the zeros of 6x^2+5x+1=0

The zeros of 6x^2+5x+1=0 are x=-1/3 ,x=-1/2

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6 x^{2} + 5 x + 1 = 0

x = - \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = - 0.33333 \dots, x = - 0.5

Solution steps

6 x^{2} + 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

5^{2} - 4 \cdot 6 \cdot 1 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 6}, x_{2} = \frac{- 5 - 1}{2 \cdot 6}

x = \frac{- 5 + 1}{2 \cdot 6} : - \frac{1}{3}

x = \frac{- 5 - 1}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{1}{2}

6 + 6

5 - x = 9

(\frac{3}{2})^{- 1} - 5 (2^{- 2})

- \frac{\frac{5}{3}}{- \frac{1}{8}}

4 (1)^{2}

What are the solutions to the equation 6x^2+5x+1=0 ?
The solutions to the equation 6x^2+5x+1=0 are x=-1/3 ,x=-1/2
Find the zeros of 6x^2+5x+1=0
The zeros of 6x^2+5x+1=0 are x=-1/3 ,x=-1/2