What are the solutions to the equation 18q-2q^2=0 ?

The solutions to the equation 18q-2q^2=0 are q=0,q=9

Find the zeros of 18q-2q^2=0

The zeros of 18q-2q^2=0 are q=0,q=9

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18 q - 2 q^{2} = 0

q = 0, q = 9

Solution steps

18 q - 2 q^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 q^{2} + 18 q = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 8^{2} - 4 (- 2) \cdot 0 = 18

q_{1, 2} = \frac{- 18 \pm 18}{2 ( - 2 )}

Separate the solutions

q_{1} = \frac{- 18 + 18}{2 ( - 2 )}, q_{2} = \frac{- 18 - 18}{2 ( - 2 )}

q = \frac{- 18 + 18}{2 ( - 2 )} : 0

q = \frac{- 18 - 18}{2 ( - 2 )} : 9

The solutions to the quadratic equation are:

q = 0, q = 9

x^{2} - 32 = - 4 x

\frac{3}{8} x - \frac{1}{3} x + 6 = \frac{1}{6} x

(3 x^{2} y) (x y^{3})^{2}

6 x - 6 \leq 6 (x - 1)

∣ 4 x + 8 ∣ \leq 9

What are the solutions to the equation 18q-2q^2=0 ?
The solutions to the equation 18q-2q^2=0 are q=0,q=9
Find the zeros of 18q-2q^2=0
The zeros of 18q-2q^2=0 are q=0,q=9