-x^2+5x<0

Solution

- x^{2} + 5 x < 0

x < 0 or x > 5

Interval Notation

(- \infty, 0) \cup (5, \infty)

Solution steps

- x^{2} + 5 x < 0

Factor

- x^{2} + 5 x : - x (x - 5)

- x (x - 5) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 5)) (- 1) > 0 \cdot (- 1)

Simplify

x (x - 5) > 0

Identify the intervals

x < 0 or x > 5

(x + 15)^{4}

\frac{7 !}{3 ! ( 7 - 3 ) !}

10 j - 30 j^{2} + 15 j^{4} - 5 j^{3}

x^{2} - 10 x + 34 = 0

\frac{x ^{- 3}}{x ^{- 4}}