What is (8i)/(-4-4i) ?

The solution to (8i)/(-4-4i) is -1-i

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simplify (8i)/(-4-4i)

simplify

\frac{8 i}{- 4 - 4 i}

- 1 - i

Solution steps

\frac{8 i}{- 4 - 4 i}

Multiply by the conjugate

\frac{- 4 + 4 i}{- 4 + 4 i}

= \frac{8 i ( - 4 + 4 i )}{( - 4 - 4 i ) ( - 4 + 4 i )}

Simplify

\frac{8 i ( - 4 + 4 i )}{( - 4 - 4 i ) ( - 4 + 4 i )} : \frac{- 32 i - 32}{32}

= \frac{- 32 i - 32}{32}

Rewrite in standard complex form:

- 1 - i

= - 1 - i

\frac{1}{2} a^{2} + \frac{3}{2} a

- \frac{1}{3} + \frac{5}{6}

\frac{6}{5} - \frac{2}{5}

5 \frac{1}{3} + (- 2)

lo g_{0.5} (100)