What is expand (x+5)(x+3)(x-1) ?

The solution to expand (x+5)(x+3)(x-1) is x^3+7x^2+7x-15

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expand (x+5)(x+3)(x-1)

expand

(x + 5) (x + 3) (x - 1)

x^{3} + 7 x^{2} + 7 x - 15

Solution steps

(x + 5) (x + 3) (x - 1)

Expand

(x + 5) (x + 3) (x - 1) : (x^{2} + 8 x + 15) (x - 1)

= (x^{2} + 8 x + 15) (x - 1)

Distribute parentheses

= x^{2} x + x^{2} (- 1) + 8 xx + 8 x (- 1) + 15 x + 15 (- 1)

Simplify

x^{2} x + x^{2} (- 1) + 8 xx + 8 x (- 1) + 15 x + 15 (- 1) : x^{3} + 7 x^{2} + 7 x - 15

= x^{3} + 7 x^{2} + 7 x - 15

\frac{- 2 x ^{2}}{x ^{2}}

4 lo g_{4} (2)

\frac{26.6}{69 \cdot 1 0 ^{9}}

\frac{2}{121}

\frac{11 2}{2}

What is expand (x+5)(x+3)(x-1) ?
The solution to expand (x+5)(x+3)(x-1) is x^3+7x^2+7x-15