What are the solutions to the equation 12x^2+72x=0 ?

The solutions to the equation 12x^2+72x=0 are x=0,x=-6

Find the zeros of 12x^2+72x=0

The zeros of 12x^2+72x=0 are x=0,x=-6

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12 x^{2} + 72 x = 0

x = 0, x = - 6

Solution steps

12 x^{2} + 72 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

7 2^{2} - 4 \cdot 12 \cdot 0 = 72

x_{1, 2} = \frac{- 72 \pm 72}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 72 + 72}{2 \cdot 12}, x_{2} = \frac{- 72 - 72}{2 \cdot 12}

x = \frac{- 72 + 72}{2 \cdot 12} : 0

x = \frac{- 72 - 72}{2 \cdot 12} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

\frac{3 ( \frac{3}{2} ) + 2}{( \frac{3}{2} ) + 1}

- 54 x^{2} - 75 x - 24

(7 x y)^{2}

- 2 < \frac{3 - x}{8} \leq 5

6^{8}

What are the solutions to the equation 12x^2+72x=0 ?
The solutions to the equation 12x^2+72x=0 are x=0,x=-6
Find the zeros of 12x^2+72x=0
The zeros of 12x^2+72x=0 are x=0,x=-6