What is (6x^2+3x)/(2x^2+7x+3) ?

The solution to (6x^2+3x)/(2x^2+7x+3) is (3x)/(x+3)

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simplify (6x^2+3x)/(2x^2+7x+3)

simplify

\frac{6 x ^{2} + 3 x}{2 x ^{2} + 7 x + 3}

\frac{3 x}{x + 3}

Solution steps

\frac{6 x ^{2} + 3 x}{2 x ^{2} + 7 x + 3}

Factor

6 x^{2} + 3 x : 3 x (2 x + 1)

= \frac{3 x ( 2 x + 1 )}{2 x ^{2} + 7 x + 3}

Factor

2 x^{2} + 7 x + 3 : (2 x + 1) (x + 3)

= \frac{3 x ( 2 x + 1 )}{( 2 x + 1 ) ( x + 3 )}

Cancel the common factor:

2 x + 1

= \frac{3 x}{x + 3}

(x + a)^{2} + 8 (x + a) + 8

2 \times 3

6^{3 l o g_{6} (2)}

csc^{2} (θ) sin (θ)

- \frac{2.1}{5.6}

What is (6x^2+3x)/(2x^2+7x+3) ?
The solution to (6x^2+3x)/(2x^2+7x+3) is (3x)/(x+3)