What is factor x^4-4x^3-6x^2+4x+5 ?

The solution to factor x^4-4x^3-6x^2+4x+5 is (x-1)(x+1)^2(x-5)

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factor x^4-4x^3-6x^2+4x+5

factor

x^{4} - 4 x^{3} - 6 x^{2} + 4 x + 5

(x - 1) (x + 1)^{2} (x - 5)

Solution steps

x^{4} - 4 x^{3} - 6 x^{2} + 4 x + 5

Use the rational root theorem

= (x - 1) \frac{x ^{4} - 4 x ^{3} - 6 x ^{2} + 4 x + 5}{x - 1}

\frac{x ^{4} - 4 x ^{3} - 6 x ^{2} + 4 x + 5}{x - 1} = x^{3} - 3 x^{2} - 9 x - 5

= (x - 1) (x^{3} - 3 x^{2} - 9 x - 5)

Factor

x^{3} - 3 x^{2} - 9 x - 5 : (x + 1) (x + 1) (x - 5)

= (x - 1) (x + 1) (x + 1) (x - 5)

Apply exponent rule:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x - 1) (x + 1)^{2} (x - 5)

(5 z + 5)^{3}

\frac{3 3}{2 3 - 6}

\frac{24}{3.2 \times 2}

364

(x + 8) (8 x + 2)

What is factor x^4-4x^3-6x^2+4x+5 ?
The solution to factor x^4-4x^3-6x^2+4x+5 is (x-1)(x+1)^2(x-5)