What are the solutions to the equation 4x^2-6x-3=0 ?

The solutions to the equation 4x^2-6x-3=0 are x=(3+sqrt(21))/4 ,x=(3-sqrt(21))/4

Find the zeros of 4x^2-6x-3=0

The zeros of 4x^2-6x-3=0 are x=(3+sqrt(21))/4 ,x=(3-sqrt(21))/4

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4 x^{2} - 6 x - 3 = 0

x = \frac{3 + 21}{4}, x = \frac{3 - 21}{4}

Decimal Notation

x = 1.89564 \dots, x = - 0.39564 \dots

Solution steps

4 x^{2} - 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 6)^{2} - 4 \cdot 4 (- 3) = 221

x_{1, 2} = \frac{- ( - 6 ) \pm 2 21}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 21}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 21}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 21}{2 \cdot 4} : \frac{3 + 21}{4}

x = \frac{- ( - 6 ) - 2 21}{2 \cdot 4} : \frac{3 - 21}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 21}{4}, x = \frac{3 - 21}{4}

∣ x + 4 ∣ = ∣ 2 x - 1 ∣

- 8 + 4 x > - 24

27 x^{3} - 8 y^{3}

3 - \frac{4}{5}

2 x^{3} + 3 x^{2} - 12 x

What are the solutions to the equation 4x^2-6x-3=0 ?
The solutions to the equation 4x^2-6x-3=0 are x=(3+sqrt(21))/4 ,x=(3-sqrt(21))/4
Find the zeros of 4x^2-6x-3=0
The zeros of 4x^2-6x-3=0 are x=(3+sqrt(21))/4 ,x=(3-sqrt(21))/4