What is (4x^2+4x+1)/(4x^2-1) ?

The solution to (4x^2+4x+1)/(4x^2-1) is (2x+1)/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4x^2+4x+1)/(4x^2-1)

simplify

\frac{4 x ^{2} + 4 x + 1}{4 x ^{2} - 1}

\frac{2 x + 1}{2 x - 1}

Solution steps

\frac{4 x ^{2} + 4 x + 1}{4 x ^{2} - 1}

Factor

4 x^{2} + 4 x + 1 : (2 x + 1)^{2}

= \frac{( 2 x + 1 ) ^{2}}{4 x ^{2} - 1}

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= \frac{( 2 x + 1 ) ^{2}}{( 2 x + 1 ) ( 2 x - 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(2 x + 1)^{2} = (2 x + 1) (2 x + 1)

= \frac{( 2 x + 1 ) ( 2 x + 1 )}{( 2 x + 1 ) ( 2 x - 1 )}

Cancel the common factor:

2 x + 1

= \frac{2 x + 1}{2 x - 1}

\frac{x ^{6}}{x ^{3}}

- \frac{\frac{75}{16}}{- \frac{5}{4}}

23 \times 2

1 - Q (0.9)

What is (4x^2+4x+1)/(4x^2-1) ?
The solution to (4x^2+4x+1)/(4x^2-1) is (2x+1)/(2x-1)