What are the solutions to the equation (4x+3)(x+1)=1 ?

The solutions to the equation (4x+3)(x+1)=1 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8

Find the zeros of (4x+3)(x+1)=1

The zeros of (4x+3)(x+1)=1 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8

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(4 x + 3) (x + 1) = 1

x = \frac{- 7 + 17}{8}, x = \frac{- 7 - 17}{8}

Decimal Notation

x = - 0.35961 \dots, x = - 1.39038 \dots

Solution steps

(4 x + 3) (x + 1) = 1

Expand

(4 x + 3) (x + 1) : 4 x^{2} + 7 x + 3

4 x^{2} + 7 x + 3 = 1

Move

1

to the left side

4 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

7^{2} - 4 \cdot 4 \cdot 2 = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 4}, x_{2} = \frac{- 7 - 17}{2 \cdot 4}

x = \frac{- 7 + 17}{2 \cdot 4} : \frac{- 7 + 17}{8}

x = \frac{- 7 - 17}{2 \cdot 4} : \frac{- 7 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 7 + 17}{8}, x = \frac{- 7 - 17}{8}

12 x^{2} - 3

6 ∣ 2 + 4 k ∣ = 84

∣ x - 1 ∣ < 1

4 x - 60 = 30 - x

\frac{1}{( \frac{3}{5} )}

What are the solutions to the equation (4x+3)(x+1)=1 ?
The solutions to the equation (4x+3)(x+1)=1 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8
Find the zeros of (4x+3)(x+1)=1
The zeros of (4x+3)(x+1)=1 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8