What is factor 16y^4-81 ?

The solution to factor 16y^4-81 is (4y^2+9)(2y+3)(2y-3)

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factor 16y^4-81

factor

16 y^{4} - 81

(4 y^{2} + 9) (2 y + 3) (2 y - 3)

Solution steps

16 y^{4} - 81

Apply exponent rules

= (4 y^{2})^{2} - 9^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 y^{2})^{2} - 9^{2} = (4 y^{2} + 9) (4 y^{2} - 9)

= (4 y^{2} + 9) (4 y^{2} - 9)

Factor

4 y^{2} - 9 : (2 y + 3) (2 y - 3)

= (4 y^{2} + 9) (2 y + 3) (2 y - 3)

(6 x + 8) (5 x - 8)

51024

\frac{16 + 18 + 4}{6 + 6}

854 - 46

(12 x)^{2}

What is factor 16y^4-81 ?
The solution to factor 16y^4-81 is (4y^2+9)(2y+3)(2y-3)