What is (x^3+3x^2+2x)/(x^2-x-6) ?

The solution to (x^3+3x^2+2x)/(x^2-x-6) is (x(x+1))/(x-3)

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simplify (x^3+3x^2+2x)/(x^2-x-6)

simplify

\frac{x ^{3} + 3 x ^{2} + 2 x}{x ^{2} - x - 6}

\frac{x ( x + 1 )}{x - 3}

Solution steps

\frac{x ^{3} + 3 x ^{2} + 2 x}{x ^{2} - x - 6}

Factor

x^{3} + 3 x^{2} + 2 x : x (x + 1) (x + 2)

= \frac{x ( x + 1 ) ( x + 2 )}{x ^{2} - x - 6}

Factor

x^{2} - x - 6 : (x + 2) (x - 3)

= \frac{x ( x + 1 ) ( x + 2 )}{( x + 2 ) ( x - 3 )}

Cancel the common factor:

x + 2

= \frac{x ( x + 1 )}{x - 3}

1 0^{0.75}

10 - (x + 2)

z \cdot z^{- 1}

834 \cdot 9.8

\frac{108}{8}

What is (x^3+3x^2+2x)/(x^2-x-6) ?
The solution to (x^3+3x^2+2x)/(x^2-x-6) is (x(x+1))/(x-3)